filenames - Return the list of current filenames
filenames ();
Return a string with all the filenames currently being process.
The first filename is the request. If the initial filename use a generate, than this will be the next filename, etc.
Note: In the followings examples, the _ between the { should be removed to make it work.
{_{ filenames(); }}
Written by Pierre Laplante, <laplante@sednove.com>
1.0 2015-01-17 22:50:14 laplante@sednove.com